Please answer questions 006,007,008,009 only Thanks This print-out should have 9
ID: 1524261 • Letter: P
Question
Please answer questions006,007,008,009 only
Thanks This print-out should have 9 questions. 003 (part 3 of 5) 10.0 points Multiple choice questions may continue on What is the z-component of vector r from the next column or page find all choices the starting point (position O) to the city C? before answering. Answer in units of km. 001 (part 1 of 5) 3.0 points 004 (part 4 of 5) 10.0 points A commuter airplane starts from an airport located at the origin. First it flies to city What is the y component of vector A located 84 km away from the airport in Answer in units of km. a direction 26° North of East. Next it flies 005 (part 5 of 5) 10.0 points 57.1 km at 25 West of North to city B. Finally What is the direction of the final position it flies 176 km due West to city C. vector in degrees West of North; i.e., what is the angle Use counterclockwise as the positive angular direction, measured between -180° and +180° from North; (e.g., East is Answer in units of What is the z-component of the vector i? 006 (part 1 of 2) 10.0 points Consider E to be the positive z axis and N to A car travels 26.5 km due north and then be the positive y axis. 26.9 km in a direction 64.1 ° west of north. 2. br btan B bcos B 6. br -bsin 8 002 (part 2 of 5) 3.0 points Find the magnitude of the car's resultant What is the y component of the vector b? displacement Answer in units of km. -boos 007 (part 2 of 2) 10.0 points bsin B Calculate the direction of the car's resul. tant displacement, measured counterclock- wise from the northerly direction. Answer in units of 008 10.0 points A person walks 23 m East and then walks 38 m at an angle 41 North of East. 6. by btanB What is the magnitude of the total dis-
Explanation / Answer
Q6.
let north be along +ve y axis and east be along +ve x axis
let i and j are unit vectors along +ve x and +ve y axis repsectively
then total displacement in unit vector notation
=26.5 j + 26.9*(-sin(64.1) i + cos(64.1) j))
=-24.1981 i + 38.25 j
magnitude of total displacement=sqrt(24.1981^2+38.25^2)
=45.2615 km
Q7.
angle with north=arctan(24.1981/38.25)
=32.3186 degrees
Q8. total displacement=23 i + 38*(cos(41) i + sin(41) j)
=51.679 i + 24.9302 j
magnitude of total displacement=sqrt(51.679^2+24.9302^2)
=57.378 m
Q9.vector A=4 i -2 j
vector B=4 i + 5 j
vector C=-i -4 j
vector D=-2i + 5j
then R=-A+B+C-D=-4i+2j + 4i + 5j -i-4j+2i-5j
=i-2j
hence option 2 is the correct figure.