Question
Find diagram and the values given below to find each quantity related to the electric field at point in due to q_1 and q_2 q_1 = - 5.9 mu C, q_2 = 5.2 mu C, a = 0.541 m, b = 0.314 m, r_1 = 1.751_m 0.5631_m 1.618_m 0.8718_m 0.7013_m 0.8253_m r_2 = 0.7581_m 1.4_m 0.5075_m .6989_m 0.8839_m 1.4_m Phi_1 = 51.9 degree 76.05 degree 73.86 degree 33.99 degree 26.12 degree 71.04 degree Phi_2 = 47.03 degree 65.53 degree 53.13 degree 77.06 degree 94.43 degree 68.79 degree theta_1 = 333.9 degree 222.3 degree 232 degree 316.9 degree 274.5 degree 231.9 degree theta_2 = - 8743 degree - 63.53 degree - 43.01 degree - 92.92 degree - 61.3 degree -53.38 degree
Explanation / Answer
Q15.
r1=sqrt(a^2+c^2)=sqrt(0.541^2+0.69^2)=0.8768 m
hence option d is correct.
Q16. r2=sqrt(b^2+c^2)=sqrt(0.314^2+0.69^2)=0.758 m
hence option a is correct.
Q17. phi_1=arctan(c/a)=arctan(0.69/0.541)=51.9015 degrees
hence option a is correct.
Q18. phi_2=arctan(c/b)=arctan(0.69/0.314)=65.531 degrees
hence option b is correct.