A small block of mass m and charge Q is placed on an insulated, frictionless, in

Question

A small block of mass m and charge Q is placed on an insulated, frictionless, inclined plane of angle theta as in the figure below. An electric field is applied parallel to the incline. Find an expression for the magnitude of the electric field that enables the block to remain at rest. (Use any variable or symbol stated above along with the following as necessary: g for the acceleration due gravity.) E = If m = 5.76 g, Q = -6.93 mu C, and theta = 26.5 degree, determine the magnitude and the direction of the electric field that enables the block to remain at rest on the include. Magnitude Your response differs from the correct answer by more than 10 percentage. Double check your calculations. N/C direction down the incline

Explanation / Answer

a.)

Electric field strength is measured as the force per coulomb

force required (to balance gravity acting down the slope ) F= mg sin

E = F/q = mg sin/q

B.)

E = F/q = mg sin/q

E = 5.76*10^-3*9.81 *Sin(26.5) / (-6.93*10^-6)

E =3638.19 N/C

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