Please answer all three and show simple steps please Some people in a hotel are
ID: 1530881 • Letter: P
Question
Please answer all three and show simple steps please Some people in a hotel are dropping water balloons from their open window on to the ground below. The balloons take 0 15 s to pass your 1.6-m-tall window. Where should security look for the raucous hotel guests? 5 m above the top of your window 10 m above the top of tout window 15 m above the top of your window 20 in above the top of your window 40 m above the top of your window A player shoots a basketball from the free-throw line and the basketball lands in the basket. Now. suppose the player made the same shot from free-throw line on Mars where the acceleration of gravity has a magnitude of 3.8 m/s^2. From the choices below, what could the player do to adjust her shot so that the basketball still goes in the goal? Shoot the basketball at the same launch angle, but at a higher speed Shoot the basketball at the same speed, but at a larger launch angle Jump straight up and. while in the air, shoot the basketball at the same speed aim same launch angle None of the above A battleship launches a shell horizontally at 100 m/s from the ships deck than. 50 m above the water. The shell is intended to hit a target buoy in the water. However, when the shell is fired, a tailwind causes the shell to have a total acceleration of a^rightarrow = (2.0 m/s^2)i - (9.81 m/s^2)j. As a result, the shell misses its target How far away from the buoy will the shell land? (To clarify, if there was no tailwind, the shell would hit the buoy.) 5 m 10 m 20 m 30 m 40 mExplanation / Answer
1) time t = 0.15s accleration a = 9.81 m/s2, distance travelled s = 1.6m
applying S = ut + 1/2*a*t2 we get, 1.6 = u*0.15 + 0.5*9.81*0.152 which givs us u = 9.93 m/s
Hence the speed of balloons just it reaches the window is 9.93 m/s. So we have to calculate the distance travelled by balloon with initial velocity zero when it reaches this speed. Here u = 0, v(final speed) = 9.93 m/s, a = 9.81 m/s2
v2 = u2 + 2aS => 9.932 = 02 + 2*9.81*S => S = 5.02 m.
Hence option A) is correct answer,
2) Lower gravity means longer time before balls come down and longer time means ball will travel horizontally longer missing the basket. Hence we want the ball to have lower horizontal velocity which can be done by throwing the ball at higher angle. option(B)
3) We know that shell will hit the ground as soon as it travels 50m vertically downward. Hence we just calculate time by this and use horizontal distance travelled in this time with 2m/s2 accleration.
s1 = u*t + 1/2a*t2 => 50 = 0*t + 0.5*9.81*t2 => t = 3.2 s
also S = u*t + 1/2at2 => S = 0*3.2 + 0.5*2*3.22 = 10.24 m Hence answer is option B) 10 m