The solution must include the following parts: given or known, find, basic or ba
ID: 1531410 • Letter: T
Question
The solution must include the following parts: given or known, find, basic or basic relation(s), the symbolic or symbolic solution, and the numerical or numerical solution. All work, units, and conv erosions to standard units must be shown and must be correct. Calculate the true mass (in vacuum) of a piece of aluminum (SG 2.70000) whose apparent mass is 3.30000 kg when weighed in air (SG 0.00129000). (Express your answer to six significant figures.) Symbolic solution (Find completely expressed in terms of given): Numerical solution (show correct units):Explanation / Answer
apparent mass = mass - mass of displaced air
= rho(aluminum) V - rho(air) V
= (rhoAl - rhoair) V
Sol the volume of aluminum is:
V = apparent mass / (rhoAl - rhoair) = 3.3 kg / (2830 - 1.225) kg/m3 = 0.001166583 m3
The true mass is:
m = rhoAl V = 2830 kg/m3 * 0.001166583 m3 = 3.30142989 kg