Question #3 A new physical quantity is the electric field divided by acceleratio

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Question #3

A new physical quantity is the electric field divided by acceleration, what are reasonable metric units for this quantity? kg*m*C/s^2 kg*m/C kg/s kg*C/s kg/C A -40 nC charge experiences a force of 1.2 N SE, what is the electric field at the location of the charge? 30 MN/C NW 4.8 MN/C SE 30 MN/C SE 48 MN/C SW 3.0 MN/C SE A 40 mu C charge is located at (0 m, 7 m), with a - 50 mu C charge located at (0 m, 2 m) a 20 mu C charge located at (0 m, -4 m). Use this information for the next two question What is the net electric force on the 40 mu C charge? -0.66 N -0.72 N +5.95 times 10^-2 N +0.78 N At which of the following points would the electric potential difference, with r to infinity, be negative?

Explanation / Answer

C)

WE KNOW THAT

F = q*E

and you have the force and the charge

E= (1.2/40)*10^9 N/C

= 30 MN/CSE

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