After the electrons pass through the anode, they arc moving at a speed of 9.076
ID: 1534109 • Letter: A
Question
After the electrons pass through the anode, they arc moving at a speed of 9.076 times 10^6 m/s. They next pass between a pair of parallel plates [(A) in the figure]. The plates each have an area of 2.78 cm by 2.78 cm and they are separated by a distance of 0.468 cm. The uniform electric field between them is 1.00 times 10^3 N/C and the plates are charged as shown. The electrons then pass between another set of parallel plates [(B) in the figure]. These plates also have an area of 2.78 cm by 2.78 cm and arc separated by a distance of 0.468 cm. In what direction must the field be oriented so that the electrons arc deflected vertically upward? If we neglect the gravitational force, how strong must the field be between these plates in order for the electrons to be deflected by 2.22 mm? How much less will the electrons be deflected if we do include the gravitational force? Give answer in scientific notation.Explanation / Answer
if we include gravitional force the deflection of electrons is given by from the kinematic equation
s= 1/2 * g ( del t)^2
= 1/2 * 9.8 ( xi/ vi)^2
= 1/2 * 9.8 ( 0.0278/9.076 * 10^6)^2
=4.59 * 10^-17 m