Calculate the maximum power that can be dissipated through the load resistor R L

Question

Calculate the maximum power that can be dissipated through the load resistor RL in a DC circuit with voltage source V=16 V, internal resistance Ro=33 and load resistor RL. Express the answer to one decimal place.

QUESTION 3 4 points Save Answer Calculate the maximum power that can be dissipated through the load resistor RL in a DC circuit with voltage source V-16 V, internal resistance Ro 33 Q and load resistor RL. Express the answer to one decimal place. DC Supply red OH RO Question Completion Status: black O and O Imaginary box for "real supply with RO

Explanation / Answer

Since RL and Ro are in series

net resistance of the circuit = RL + 33ohm

Now current in circuit = V/Rnet = 16/RL +33

Maximum power dissipated = I^2RL = (16/(RL +33))^2/RL

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