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I only need the answer for part B. I included the screenshot with part A to incl

ID: 1536318 • Letter: I

Question

I only need the answer for part B. I included the screenshot with part A to include the question and chart.

tem 10 Consider the juncion of three wires as shown in the diagram. (Figure 1) Figure 1 of 1 Wire 1 Wire 2 Wire 3 The magnitudes of the current density and the diameters for wires 1 and 2 are given in the table. The current directions are indicated by the arrows Current density Diameter Wire (A/ 2 2.6 5.6 Part A Find the current 13 in wire 3. Express your answer in a to two significant figures. Call current out of the junction positive and current into the junction negative Hints My Answers Give Up Review Part Submit Part B

Explanation / Answer


current density is J3 = I3/A3

for wire 1 ,J1 = I1/A1
I1 = J1*A1 = 2.4*(pi*(d/2)^2) = 2.4*(3.142*(1.7/2)^2) = 5.44 A

I2 = J2*A2 = 5.6*(3.142*(2.6/2)^2) = 29.73 A

Using junction rule

I1-I2+I3 = 0


5.44-29.73+I3 = 0

I3 = 24.29 A towards the junction

then

B) J3 = I3/A3 = 24.29/(pi*(d/2)^2) = 24.29/(3.142*(1.5/2)^2)

J3 = 13.74 A/mm^2