I post my wrong answers on the right for parts C which i need the solution for.

Question

I post my wrong answers on the right for parts C which i need the solution for.

Mastering Physics: HW 29 Google Chrome Secure https:// session masteringphysics.com assignment ProblemIDJ76304163 /myct/itemView? PHYSICS II Help Close HW29 Problem 29.3 previous 2 of 16 next Problem 29.3 Correct A proton moves along the z-axis with vz 1.0 x 10 m/s Part B As it passes the origin, what are the strength and direction of the magnetic field at the (0 cm, 1 cm, Mastering Physics: HW29 Goo... 0 cm) position? Give your answer using unit vectors. Secure https:// session masteringphysics.com /my Express your answer in terms of the unit vectors i, j, and k. Use the "unit vector' button to denote unit vectors in your answer. ANSWER 1: Deduction: -1% 1.6.10 B 8.1018 k T Submit My Answers Give Up Your answer either contains an incorrect Correct numerical multiplier or is missing one ANSWER 2: Deduction: -1% Part C 8.10 As it passes the origin, what are the strength and direction of the magnetic field at the (0 cm, -2 cm, 0 cm) position? Give your answer using unit vectors. Express your answer in terms of the unit vectors i, j, and k. Use the "unit vector' button to Your answer either contains an incorrect denote unit vectors in your answer. numerical multiplier or is missing one ANSWER 3: Deduction: -1% 18 8.10 B- 8.10 18 -k Your answer either contains an incorrect Submit My Answers Give Up numerical multiplier or is missing one Incorrect, Try Again, 3 attempts remaining Return to Current Item Continue Provide Feedback

Explanation / Answer

C) magnetic field due to moving charged particle,

B = (mue/(4*pi))*(q*v/r^2)

= (4*pi*10^-7/(4*pi))*(1.6*10^-19*1*10^7/0.02^2)

= 4*10^-16 T

here the direction of magnetic field is towards -z axis.

so,

B = - 4*10^-16 k T

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