The dielectric between the plates is now replaced by two media, in different pro

Question

The dielectric between the plates is now replaced by two media, in different proportions. If the capacitor is viewed edge-on as shown, Teflon fills the lower volume between the plates, to a fraction of 0.60 of the total, and Mylar fills the remainder. What does the meter read now? (Note: This capacitor can be treated as two capacitors in parallel; the total capacitance is the sum of the capacitances of the two parts, each evaluated for its own geometry.)

What is the separation of the plates?
Correct, computer gets: 1.85e+00 mm

Explanation / Answer

here it was an arrangemnet of two capacitors which are in parallel

then Cnet = C1+C2

Cnet = (k1*eo*0.6*A/d)+(k2*eo*0.4*A/d)

Cnet = ((0.6*k1)+(0.4*k2))*Co

Cnet = ((0.6*2.1)+(0.4*3.1))*149*10^-12 = 3.72*10^-10 F = 372 pF

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