In a simple AC circuit shown on the right, C=0.075 FL=1.9 H, R=27 O, amd O=I max

Question

In a simple AC circuit shown on the right, C=0.075 FL=1.9 H, R=27 O, amd O=I max sin (omega t), where Imax=5.5 A and omega=95 rad/s.

(56%) Problem 2: In a simple AC circuit shown on the right, C 0,075 F, L 1.9 H. R 27 O, and I Ima Sin(dot), where I, max 5.5 A and 95 rad/s Randomized Variables C 0.075 F L 1.9 H R 27 O Ima 5.5 A 95 rad/s AV Otheexpertta.com 83 10% Part (e) Express the maximum potential difference between a and b. ab, max in terms of and YC. Iman A 10% Part on Calculate the numerical value of 4Vab max in volts. A 10% Part (g) Express the maximum potential difference between b and c, 4Vi max in terms of I and R. bc, max 10% Part Calculate the numerical value of4Vbe man in volts. A 10% Part (i Express the maximum potential difference between c and d, 4Vodmar in terms of I and X Grade Summary Deductions Potential 100% cas,max B 7 8 9 HOME Submissions Attempts remaining: 3 4 5 6 40% per attempt) 1 2 3 detailed view t XC XL BACKSPACE DEL CLEAR I give up Submit Hints 4% deduction per hint. Hints remaining: 1 Feedback 5% deduction per feedback. in Volts

Explanation / Answer

part e )

voltage drop on capacitor

Vab = Imax *Xc

part f)

Xc = 1/w*C = 0.14 ohm

Imax = 5.5

Vabmax = 0.772 V

part g )

Vbcmax = Imax *R

part h )

Vbcmax = 5.5 * 27 = 148.5 V

part i )

Vcdmax = Imax*XL

part j )

XL = w*L = 180.5

Vcdmax = 5.5 * 180.5 = 992.75 V

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