Question
A 1500 kg car drives at the bottom of a through with an effective radius of 80 m at speed of 20 m/s. What is the normal force of the road on the car? A 0.06 bullet moving horizontally a 300 m/s collides with and passes through a 2kg block, initially at rest. The ballet exits the block at 100 m/s. This cause the block to slide along the floor a distance of 12 m before stopping. What is the coefficient of fiction between the block and the floor? A 0.13 kg rubber ball dropped from a height of 2.1 m on a height of. If the ball is in contact with the floor for 0.0856, then what is the average force of the bat on the ball? What is the triangle between A^- = (-36, -4) and the positive y-axis?
Explanation / Answer
Writing equations of motion for the car at the trough
N-mg = m*a
a is the centripetal accelaration = v^2/R
then Normal force N = mg + (m*v^2/R)
N = (1500*9.8)+(1500*20^2/80)
N = 22200 N