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Problem 5 please C LON-CAPA. The Learning x LON-CAPA The Leaming x CChegg study

ID: 1552493 • Letter: P

Question

Problem 5 please

C LON-CAPA. The Learning x LON-CAPA The Leaming x CChegg study l Guided sc x C G LON CAPA The Learnir x C LON CAPA The Learning x C LON CAPA- The Learning x C capa cgill.ca/uplo lt 14865760669837301486576085 pag bottom wire? Give a sign if I is parallel to In- and a sign if I2 is opposite to Il The mass density of copper is 8.93x10 kg/m3 1.79x102 A 40 You are correct. Computers answer now shown above. Previous Trie Your receipt is 157-3681 Problem 5 In the figure below a long straight wire carries a current of 1.4 A. Find the magnitude of the net force on a Tigid square loop of wire of side 1, equal to 705 cm The center of the loop is 10.40 cm from the wire and the loop can ies a cinTent of 10.0 A 9.53 10n N Find the force on the bottom segment and on the top segment, then add them comectly. submit Answer IDConect Tries 4/6 P Thies hours, 40 minute La Problem 6 The figure shows a cylinder of mass 3kg. radaus 5.6cm and length 54cm with 110tums of wire wrapped around it length o that the plane of the wine loop contains the axis of the cylinder. What the least current which while flownng through the loop will prevent the cylinder from rolling down an inclined plane of inclination 29 in the presence of a vertical magnetic field ofB 0.2T? The plame of the windings is parallel to the inclined plane. A 619

Explanation / Answer

force on side parallel and near to long wire,

(it will repel that currents are in opposite direction)

F1 = u0 I1 I2 L / (2 pi (d - (L/2)))

F1 = (4pi x 10^-7) (1.4 x 10 x 0.0705) / (2 x pi x (0.1040 - (0.0705/2)))

F1 = 2.87 x 10^-6 N away from wire


Net force on these two perpendicular wire sides will be zero due to long wire,


force on bottom segment.

F2 = (4 pi x 10^-7) (1.4 x 10 x 0.0705) / (2 x pi x (0.1040 + (0.0705 / 2)))

F2 = 1.418 x 10^-6 N towards the wire

Fnet = F1 - F2 = 1.45 x 10^-6 N ........Ans

away from wire