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Secure https://session.masteringphysics.com/myct/itemview?assignment ProblemID 7

ID: 1554491 • Letter: S

Question

Secure https://session.masteringphysics.com/myct/itemview?assignment ProblemID 75879283 Spring 2017 PHYS191 20997 L04. HW CHS tem 1 Item 1 Part A Find the maximum tension in the chain. A72.7-kg wrecking ball hangs from a uniform heavy- duty chain having a mass of 25.3 kg (Use 9.80 m/s for the gravitational acceleration at the earth's surface.) Tmax Submit My Answers Give Up Part B Find the minimum tension in the chain. Trnin Submit My Answers Give Up Part C What is the tension at a point three-fourths of the way up from the bottom of the chain?

Explanation / Answer

A)

Max tension = (Massball + Massrope)*(9.8 m/s2)
Tmax =(72.7kg + 25.3kg)*(9.8)

Tmax = 960.4 N

B)

Min tension = (Mball)*(9.8 m/s2)
Tmin = (72.7kg)*(9.8)

Tmin = 712.46 N


C)

3/4 from bottom of the chain: Since you have to use only 75% of the chain take the mass of the chain (25.3kg) and multiply it by 0.75. This equals 18.975kg

T3/4 = (18.975kg + 72.7kg)*(9.8)

T3/4 = 898.415 N