Three beads are placed on the vertices of an equilateral triangle of side d = 45
ID: 1557865 • Letter: T
Question
Three beads are placed on the vertices of an equilateral triangle of side d = 45 cm. The first bead of mass m_1 = 150 g is placed on the top vertex. The second bead of mass m_2 = 55 g is placed on the left vertex. The third bead of mass m_3 = 75 g is placed on the right vertex. Write a symbolic equation for the horizontal component of the center of mass relative to the left vertex of the triangle. Find the horizontal component of the center of mass relative to the left vertex, in centimeters. Write a symbolic equation for the vertical component of the center of mass relative to the base of the triangle. Find the vertical component of the center of mass relative to the base of the triangle, in centimeters.Explanation / Answer
X cm = [m1*(d/2) + m3* (d)]/(m1 + m2 + m3)
now m1 = 150 gm ,
m2 = 55 gm,
m3 = 75 gm,
d= 4.5 cm
Now just putting the values
X cm =[ 150 *(4.5/2) + 75* (4.5)]/(150 + 55 + 75) = 2.41 cm <---------Answer