Problem 1: Suppose the speed of light in a particular medium is 2.012 x 10 m/s.
ID: 1557932 • Letter: P
Question
Problem 1: Suppose the speed of light in a particular medium is 2.012 x 10 m/s. Part (a) Calculate the index of refraction for the medium. Numeric A numeric value is expected and not an expression. Part (b) Based on the table identify the most likely substance. MultipleChoice 1) Benzene 2) Glass, crown 3) Plexiglas 4) Flourite 50 Polystyrene 60 Glycerine Problem 2: An optical fiber uses flint glass surrounded by a crown glass cladding What is the critical angle for total internal reflection in degrees? Numeric A numeric value is expected and not an expression. Medium Medium Gasses at 0 C, 1 atm Solids at 20 C 1.000293 Diamond 2.419 Air Carbon dioxide 1.00045 Fluorite 1.434 1.000139 Glass crown 1.52 Hydrogen 1.000271 Glass, flint 1.66 Ox Ice at 0°C 1.309 Liquids at 20°C 1.49 Polystyrene Benzene 1.501 Carbon Sodium chloride 1.544 disulfide 1.628 tetrachloride 1.461 Quartz, crystalline 1.544 Ethano 1.361 Quartz, fused 1.458 Water, fresh 333 Zircon 1.923 Glycerine 1.473 Otheexpertta.com n Medium Medium Solids at 20C Gasses at 0 C, 1 atm 1.000293 Diamond 2.419 Air Carbon dioxide 1.00045 Fluorite 1.434 1.000139 Glass, crown 1.52 Hydrogen 1.000271 Glass, flint 1.66 Ox Ice at 0°C 1.309 Liquids at 20°C 1.49 Polystyrene Benzene 1.501 Carbon Sodium chloride 1.544 disulfide 1.628 tetrachloride 1.461 Quartz, crystalline 1.544 Ethano 1.361 Quartz, fused 1.458 Water, fresh 333 Zircon 1.923 Glycerine 1.473 Otheexpertta.comExplanation / Answer
Problem1)
v = 2.012 x 10^8 m/s
The index of refraction of a medium is related to speed of light c in air and speed of light in that medium as follows:
n = c/v
n = 3 x 10^8 / 2.012 x 10^8 = 1.491
Hence, n = 1.49
b)Comparing the obtained value with the given values in table.
The material is polystyrene.