Consider the atom having the electron configuration 1s^2 2s^22p^6 3s^23p^1. Whic

Question

Consider the atom having the electron configuration 1s^2 2s^22p^6 3s^23p^1. Which of the following statements are correct? Check all that apply. The atom has electrons in states n = 2 and n = 3. The atom has six electrons in the state n = 2, l = 1. The atom has three electrons in the energy level for which n = 3. The atom has on one electron in the state n = 3, l= 2. The atom under consideration in this problem has electrons in three different shells corresponding to the energy levels for which n = 1, 2, 3. Moreover, it has only s and p states, so the maximum orbital quantum number is l = 1. Also, both the K shell (n = 1) and the L shell (n = 2) are fully occupied with two electrons in 1s, two electrons in 2s, and six electrons in 2p, while the M shell (n = 3), which is farther from the nucleus, is only partially occupied with two electrons in 38 and one electron in 3p. Assume that the z components of both the orbital and spin angular momenta of the electron in the 3p subshell are positive. What are the quantum numbers that describe the state of this electron? n = 2, l = 3, m = 1 n = 3, l = 2, m = 1, s = 1/2 n =3, l = 1, m = 2, s = 1/2 n =3, l = 1, m = 1 s = 1/2 n = 3, l = 1, m =-1, s = l/2 n = 3, l = 2, m = 2, s = -1/2

Explanation / Answer

for n=2,two orbits are there 2s and 2p means l=0,1 for s and p respectively, no option matched as no option with n=2 and l=0,1

for n=3,two orbits are there 3s and 3p means l=0,1 for s and p respectively,one option matched are of n=3, l=1

m for l=1 are -1,0,1 as m ranges from -1 to 1 as m can be any of these 3 values.

s=1/2 or -1/2 any

n=3,l=1,m=1,s=1/2

n=3,l=1,m=-1,s=1/2

option 4 and 5

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