Me Print Calculator Periodic Table Question 14 of 21 Sapling Learning A 0.279-kg

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Me Print Calculator Periodic Table Question 14 of 21 Sapling Learning A 0.279-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points position, xaq, the amplitude, A, the maximum speed, vrmex, the maximum magnitude of acceleration, ammo, the force constant, k, and the total mechanical energy, Etot. Number f- 1.84 Number 059 Number .364 (Saolt down for more answer blanks.) Number m/s 4.20 Incorrect. O Previous Give up & View solution a Try Again ONext Exit Explanation

Explanation / Answer

amplitude a = ( x2 - x1 )/2 = (0.423+0.279)/2 = 0.351 m

xeq = x1 + a = 0.351-0.279 = 0.072 m

T = 0.541 s.

Freuency f = 1/T = 1.848 Hz.

Maximum speed = omega A = 2pif*A = 2*pi*1.848*0.351 = 4.076 m/s

a_max = omega*v = 2*pi*1.848*4.076 = 47.328 m/s^2

k = m omega^2 = 0.279*(2*pi*1.848)^2 = 37.615 N/m

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