In problem 1-4 below, assume you are given three capacitors as follows: C1 = 1 u
ID: 1561147 • Letter: I
Question
In problem 1-4 below, assume you are given three capacitors as follows: C1 = 1 uF and 20V max. C2 = 2 uF and 50V max. C3 = 3 uF and 100V max. The maximum possible capacitance that could be attained by using the capacitors singly, or in any combination of two, or all three at once, would be (assume that the maximum voltage is not an issue): 1 uF 2 uF 6 uF none of the above The minimum possible capacitance that could be attained by using the capacitors singly, or in any Combination of two, or all three at once, would be (assume that the maximum voltage is not an issue): 1/3 uF 1/2 uF 1 uF 11/6 uF 6/11 uF Assume that all three capacitors were connected in parallel. The maximum voltage that could be safely applied to the parallel combination (without causing dielectric breakdown) would be just less than: 20V 50V 70V 100V 170V Assume that all three capacitors were connected in series. The maximum voltage that could be sa applied to the series combination (without causing dielectric breakdown) would he just less than. 20.00V 36.67V 50.00V 63.33V 100.00V When a current passes through a conductor, the actual charge carriers always move in the direction of the current. always move from higher to lower potential. always move in the same direction always have the same sign none of the aboveExplanation / Answer
4. If the capacitors are connected in series the total potential difference is simply the sum of their individual potential differences. So if for each capacitor we take maximum operating voltage and sum up them we get the maximum operating voltage upto which the series combination will be safe. Thus the maximum voltage will be
V=(20+50+100)=170V. So we should apply a voltage just less than 170V to keep the combination safe.
5. The current flows from higher potential to lower potential.In practice it is ordinarly the negatively charged electrons that do the moving-in the direction opposite the electric current i.e from lower to higher potential=(E)