Can someone please help me with the last part? Thanks. (The answer is NOT 3.07m/

Question

Can someone please help me with the last part? Thanks. (The answer is NOT 3.07m/s)

The picture shows three identical balls. The balls labelled 2 and 3 are in contact. The line connecting their centres is bisected by the path of ball 1. The speed of ball 1 is v_0 = 15.12 m/s. The trajectory of ball passes through the point at which balls 2 and 3 come into contact. Let us assume the collision is elastic. Determine the magnitude of the velocity of ball 2. Determine the magnitude of the velocity of ball 3 after the collision. Determine the magnitude of the velocity of ball 1 after the collision.

Explanation / Answer

Since the collision is elastic,

KEi = KEf

KE of ball 1 before collision = KE of ball 1 after collision + KE of ball 2 after collision + KE of ball 3 after collision

½*m*v1i^2 = ½*m*v1f^2 + ½*m*v2f^2 + ½*m*v3f2

½*15.12^2 = ½*v^2 + ½*10.5^2 + ½*10.5^2

½*m*15.12^2 = ½*m*v1f^2 + ½*m*10.5^2 + ½*m*10.5^2

v1f=2.85m/s

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