Nevada Solar One is a parabolic trough plant owned by the Alcona energy company

Question

Nevada Solar One is a parabolic trough plant owned by the Alcona energy company is rated at 64MW It does not contain any heat storage devices It is listed as a project site of 1.6 km 2 The solar collectors are designed, as claimed by Solar Electing Power Association, to produce 134 GWh/year. which would equate to a reasonable capacity factor for a plant without storage. Calculate the average output power density of the plant (in the units of W/m^2). The insolation of that area of Nevada is 225 W/m2. Based on the result you have obtained above, find the Nevada Solar One's overall efficiency.

Explanation / Answer

1.

Output energy is E = 134 GWh in one year

So output power;

P = E/t = 134X109X3600 J/(24X365X3600)

So output power density is,

Pd = P/A = P/(1.6X106 m2)

So, Pd = 9.56 W/m2, is the output power density

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2.

Efficiency is,

E = Pd/225W/m2 = [9.56 W/m2/225W/m2]X100

E = 4.25%

So the efficiency is 4.25% for the plant.

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....

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