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A small conducting spherical shell with inner radius a and outer radius b is con

ID: 1572213 • Letter: A

Question

A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d. The inner shell has a total charge of -1q and the outer shell has a total charge of +4q. It says that my answers are wrong.

Select True or False for the following statements.
True False  The total charge on the outer surface of the large shell is +3q.
True False  The radial component of the electric field in the region c < r < dis given by +4q/(4??0r2).
True False  The total charge on the inner surface of the large shell is zero.
True False  The radial component of the electric field in the region r > d is given by +4q/(4??0r2).
True False  The total charge on the inner surface of the small shell is -1q.
True False  The total charge on the outer surface of the small shell is -5q.
True False  The radial component of the electric field in the region r < a is given by -1q/(4??0r2).

Explanation / Answer

inside the conducting sphere, field strength will be zero.

So for region, c < r < d => E = 0

hence second statement is false.

from Gauss Law, if E = 0 that means Qin = 0

Qin = -   q + Qc = 0

Qc = q

and Qc + Qd = 4q

Qd = 4q - q = 3q

so first statement is True.

Qc = q
hence 3rd is false.

for r > d

E (4 pi r^2) = Qin /e0

Qin = (Qa + Qb) + (Qc + Qd) = -q + 4q = 3q

E = 3q / (4 pi e0 r^2)

False

field inside conductor is 0 hence for a < r < b => E = 0

hence for this region, Qin = 0

Qin = Qa = 0

False

-1q = 0 + Qb

Qb = - q

False

for r < a , Qin = 0

hence E = 0

False


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