A small conducting spherical shell with inner radius a and outer radius b is con
ID: 1572213 • Letter: A
Question
A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d. The inner shell has a total charge of -1q and the outer shell has a total charge of +4q. It says that my answers are wrong.
Select True or False for the following statements.
True False The total charge on the outer surface of the large shell is +3q.
True False The radial component of the electric field in the region c < r < dis given by +4q/(4??0r2).
True False The total charge on the inner surface of the large shell is zero.
True False The radial component of the electric field in the region r > d is given by +4q/(4??0r2).
True False The total charge on the inner surface of the small shell is -1q.
True False The total charge on the outer surface of the small shell is -5q.
True False The radial component of the electric field in the region r < a is given by -1q/(4??0r2).
Explanation / Answer
inside the conducting sphere, field strength will be zero.
So for region, c < r < d => E = 0
hence second statement is false.
from Gauss Law, if E = 0 that means Qin = 0
Qin = - q + Qc = 0
Qc = q
and Qc + Qd = 4q
Qd = 4q - q = 3q
so first statement is True.
Qc = q
hence 3rd is false.
for r > d
E (4 pi r^2) = Qin /e0
Qin = (Qa + Qb) + (Qc + Qd) = -q + 4q = 3q
E = 3q / (4 pi e0 r^2)
False
field inside conductor is 0 hence for a < r < b => E = 0
hence for this region, Qin = 0
Qin = Qa = 0
False
-1q = 0 + Qb
Qb = - q
False
for r < a , Qin = 0
hence E = 0
False
Ans: TFFFFFF