Student/Assignment-Responses/submit?dep-1 18013981 DEPARTMENT OF e.. Home-North

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Student/Assignment-Responses/submit?dep-1 18013981 DEPARTMENT OF e.. Home-North Carol.. E Blackboard @ NCAT- nbot -bColin@ag0- E connect rh system Salety D Industrial Hygene Two forces are applied to a tree stump to pull it out of the ground. Force FA has a magnitude of 2243 newtons and pores 30.-south ofe-whlefore i Mimagit de, 31 eMP d points due south. Using the component method, find the magnitude and direction of the resultant force FA Fo that is applied to the stump. Specily the direction with respect to due east Additional Materials Section 1.8 1P:048 G0 drawing shows. Bynser, however, forcer,isinsMoet Therefore, two A baby elephant is stuck in a mud hole. To help pull it out, game keepers use additional forces Fs and Fc the drawing is k times larger than that in part a. Find the ratio rope to appy a force F as part of the are applied, as in part b of the drawing. Each of these additional foroes has the s same magnitude F. The magnitude of the resultant force acting on the elephant ie part b of when k-1.00, (Take 8-23.0.) GO Tutorial Additional Materials Section 1.8

Explanation / Answer

Given,

Fa = 2243 at theta = 30 deg SoE

Fb = 3170 due N

In component form

Fa = Fa cos(theta) i + Fa sin(theta) j

Fa = 2243 cos30 i + 2243 sin30 j

Fa = 1942.5 i + 1121.5 j

Fb = 0i + 3170 j

Fa + Fb = 1942.5 i + 1121.5 j + 0i + 3170 j = 1942.5 i + 4291.5 j

magnitude will be:

F = sqrt (1942.5^2 + 4291.5^2) = 4710.66 N

Hence, F = 4710.66 N

theta = tan^-1(4291.5/1942.5) = 65.65 deg

Hence, theta = 65.65 deg

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