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An Fe3+ ion is located 400 nm (400 x 10-9 m, about 4000 atomic diameters) from a

ID: 1573569 • Letter: A

Question

An Fe3+ ion is located 400 nm (400 x 10-9 m, about 4000 atomic diameters) from a Cl- ion, as shown in the figure below (ions not shown to scale). 400 nm × Cl- Fe3. (a) Determine the magnitude and direction of the electric field E4 at location A, r = 101 nm to the left of the Cl-ion. magnitude direction N/C ..Select (b) Determine the magnitude and direction of the electric field Es at location B, magnitude direction Select. 101 nm to the right of the Cl-ion. N/C (c) If an electron is placed at location A, what are the magnitude and direction of the force on the electron? magnitude direction Select.

Explanation / Answer

let q1 = 3*e = 3*1.6*10^-19 = 4.8*10^-19 C

q2 = -e = -1.6*10^-19 C

a) at point A,

Enet = |E1| + |E2|

= k*q1/r1^2 + k*q2/r2^2

= 9*10^9*4.8*10^-19/(299*10^-9)^2 + 9*10^9*1.6*10^-19/(101*10^-9)^2

= 1.89*10^5 N/c

direction : towards +x axis

b) at point B,

Enet = |E1| - |E2|

= k*q1/r1^2 + k*q2/r2^2

= 9*10^9*4.8*10^-19/(501*10^-9)^2 - 9*10^9*1.6*10^-19/(101*10^-9)^2

= 1.24*10^5 N/c

direction : towards -x axis

c) F = q*Enet
= 1.6*10^-19*1.89*10^5
= 3.02*10^-14 N

direction : towards -x axis