Course Contents , » Hw 02 (Jan. 29) . Point charge inside . dubic box O Timer No

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Course Contents , » Hw 02 (Jan. 29) . Point charge inside . dubic box O Timer Notes d evaluate u, Feedback A 7.31 uC point charge is placed at the center of a cube with a volume of 8.38 m3. Calculate the electric flux through one side of the cube. -Pit Submit Answer Tries 0/12 Threaded View Chronological View Other Views Export My general preferences.on what is marked as NEW Mark NEW postsno.longer.nee NEW Units Brandon James Anderson Reply (Thu Jan 25 08:36:47 pm 2018 (EST)) What are the units for this problem? NEW Units Brandon James Anderson Reply (Thu Jan 25 08:36:48 pm 2018 (EST)) What are the units for this problem? NEW Units Anonymous 2 Reply (Thu Jan 25 10:15:38 pm 2018 (EST)) What are the units? I tried NmA2/C and it was not working any help? NEw Re: Units 2acob Keeling Loukota Reatr Thu Jan 25 11:3654 pm, 201·(EST)) I got it to work by typing N°mA2 C My settings for this discussion: 1. Display-All posts 2. Not new Once marked not NEW Change Threaded View Chronological View Osher Views Export on.ebat.is.macked.as NEW Mark NEWW Send Feedback Post Discussion

Explanation / Answer

from Gauss law,

electric flux through closed surface = Qin / e0

flux through all 6 faces = (7.31 x 10^-6) / (8.854 x 10^-12)

= 8.26 x 10^5 N m^2/ C

charge is at center and cube is symmetric so flux through all face will be same.

flux through one side of cube = (8.26 x 10^5)/6

=1.38 x 10^5 N m^2 / C

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