Please explain legibly step by step how you solved this problem. Consider the fo
ID: 1576972 • Letter: P
Question
Please explain legibly step by step how you solved this problem.
Consider the following. (LetG = 28.20 F and C2 22.20 F.) 6.00 F 9.00 V (a) Find the equivalent capacitance of the capacitors in the figure. (b) Find the charge on each capacitor. on the right 28.20 uF capacitor on the left 28.20 F capacitor on the 22.20 F capacitor on the 6.00 uF capacitor (c) Find the potential difference across each capacitor on the right 28.20 F capacitor on the left 28.20 F capacitor n the 22.20 uF capacitor on the 6.00 uF capacitorExplanation / Answer
a) 1/Ceq = 1/C1 + 1/(C2 + 6) + 1/C1
1/Ceq = 1/28.2 + 1/(22.2 + 6) + 1/28.2
Ceq = 9.4 micro F
b)
charge on the right 28.2 micro F capacitor = Ceq*V
= 9.4*9
= 84.6 micro C
charge on the left 28.2 micro F capacitor = Ceq*V
= 9.4*9
= 84.6 micro C
charge on 22.20 micro F capacitor = 84.6*22.2/(6 + 22.2)
= 66.6 micro C
charge on 6.00 micro F capacitor = 84.6*6/(6 + 22.2)
= 18 micro C
c) potential diffrence across,
on the right 28.2 micro F capacitor = 84.6/28.2
= 3 V
on the left 28.2 micro F capacitor = 84.6/28.2
= 3 V
on the 22.2 micro F capacitor = 66.6/22.2
= 3 V
on the 6 micro F capacitor = 18/6
= 3 V