Could anyone please explain why the answer is E. A gets brighter; B goes out. I

Question

Could anyone please explain why the answer is E. A gets brighter; B goes out. I check other people's explaination and chegg and they don't really make sense so PLEASE do not spam and repeat what they said. Visual or Formula explaination would be much appreciate it THANK YOU! (:

12) The lightbulbs are identical. Initially both bulbs are glowing. What happens when the switch is closed? Nothing. B) A stays the same; B gets dimmer. C. A gets brighter; B stays the same. D. Both get dimmer. E. A gets brighter; B goes out All of the

Explanation / Answer

The answer will be E only.

See when the switch was open the potential drop was shared among both the light bulbs.

And brightness depends on the power dissipated and power is

P=V 2/R

And when the switch is closed then the potential drop accross the bulb B will be zero.( You can see both the ends of the bulb are at same potential as it is connected by a wire.)

So when there is no potential difference then it will not glow at all.

And about bulb A, all the potential drop will be among itself only so it's power will increase , hence it's brightness will also increase.

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