Question 16 of 21 Sapling Learning Mapoob During a neighborhood baseball game in

Question

Question 16 of 21 Sapling Learning Mapoob During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.145-kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 16.1 m/s, shatters the glass as it passes through, and leaves the window at 11.7 m /s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball? The direction of the ball's motion Opposite the direction of the ball's motion Neither of these Calculate the magnitude of this impulse (a positive number) Number The ball is in contact with the glass for 0.0104 s as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number). Number Previous Give Up & View Solution e Check Answer 0 Next Exit- Hint

Explanation / Answer

part a )  

since there is no change in the direction of velocity , so impulse must be in the opposite direction of velocity

B option

part b )

impulse = J = change in momentum

J = m*dv

dv = vf - vi

given :

vf = 11.7 m/s

vi = 16.1 m/s

m = 0.145 kg

J = 0.145 * (11.7 - 16.1) = -0.638 N-s

magnitude of J = |J| = 0.638 N-s

part c )

J = F.dt

dt = 0.0104 s

F = J/dt = 0.638/0.0104 = 61.35 N

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