Part A: what is the force on the -10 nC charge? Part B: what is the direction of

Question

Part A: what is the force on the -10 nC charge?
Part B: what is the direction of the force on the -10nC charge in the figure? Give your answer as an angle measured cw or ccw (specify which) from the +X-axis. Enter positive value for counterclockwise angle and negative value for clockwise angle.
Problem 25.35 MasteringPhysics Problem 25.35 Part A What is the magnitude of the force F on the -10 nC charge in the figure 15 nC 5.0 nC 1.0 cm -10 nC Q Tap image to zoom Express your answer using two significant figures. Submit Give Up

Explanation / Answer

Force Due to -5 nC charge is F = 9*10^9 * 5 * 10 * 10^-18/ (.01)^2 = 4.5 * 10^-3 N

Force due to + 15nC charge is = 9*10^9 * 15 * 10 * 10^-18 / ( 10) * 10^-4   = 1.35 * 10^-3 N

So Totatal force is vector addition of two forces.

F net = sqrt ( 4.5^2 + 1.35^2 + 2 * 4.5* 1.35 * (-1/sqrt (10)) ) * 10^-3

= 4.27 * 10^-3 N

Angle of resultant vector is

Tan (alpha) = 1.35 ( 1/sqrt10)/ (4.5 - 1.35 * 3/sqrt10)

So Tan(alpha) = 0.1326

alpha = 7.55 degrees from the vertical towards down side

This is -97.55 degrees with x axis in clock wise direction

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