Please solve all parts, and show all work. Thank you! Coulombs Law and Electric

Question

Please solve all parts, and show all work. Thank you!

Coulombs Law and Electric Fields Begin Date: 1/25/2016 12:00:00 AM Due Date: 2/5/2016 12:00:00 AM End Date: 2/5/2016 12:00:00 AM (9%) Problem s: A positive charge of magnitude 21 4-5 nC is located at the origin. A negative charge Q 3.5 nC is located on the positive x-axis at x 17 cm from the origin. The point P is located v 19.5 cm above charge Os Otheexpertta.com Go A 17% Part (a) Calculate the x-component of the electric field at point P due to charge Qi. Write your answer in units of NIC. Grade Summary Deductions Potential 1000% coso tano 7 s 9 HOME Submissions Sin Attempts remaining cotan asino aC per attempt) atanO acotanO sinhO detailed vie tanho cotanh cos VO BACKSPACE DEL CLEAR Degrees O Radians bac Submit Hint I give up! Hint deduction per hint. Hints remaining Feedback: 10% deduction per feedback. A 17% Part (b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of NIC. A 17% Part (c) Calculate the y component of the electric field at point P due to the Charge Q Write your answer in units of NC A 17%. Part (d) Calculate the y-component of the electric field at point P due to both charges. Write your answer in units of N/C. 17% Part (e) Calculate the magnitude of the electric field at point P due to both charges. Write your answer in units of N/C. A 17% Part (f Calculate the angle in degrees of the electric field at point P relative to the positive x-axis

Explanation / Answer

A)

Ex,1 = (k*Q1/r1^2)*cos(theta)

r1^2 = 0.17^2+0.195^2 = 0.066925 m^2

cos(theta) = 0.17/sqrt(0.17^2+0.195^2) = 0.657

then Ex,1 = (9*10^9*4.5*10^-9/0.066925)*0.657 = 397.58 N/C

B) Ey,1 = (k*Q1/r1^2)*sin(theta)

sin(theta) = 0.195/sqrt(0.17^2+0.195^2) = 0.753

then Ey,1 = (9*10^9*4.5*10^-9/0.066925)*0.753 = 455.68 N/C

C) Ey,2 = k*Q2/r2^2 = (9*10^9*3.5*10^-9)/0.195^2 = 828.4 N/C

D) Ey = Ey,1-Ey,2 = 455.68-828.4 = -372.72 N/C

Ey = 372.72 N/C along -Y -direction

E) E = sqrt(Ex^2+Ey^2) = sqrt(397.58^2+372.72^2) = 544.96 N/C

F) theta = tan^(-1)(Ey/Ex) = tan^(-1)(-372.72/397.58) = -43.15 degrees

43.15 degrees below the positive X-axis

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