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Part A Three equal 1.60- C point charges are placed at the corners of an equilat

ID: 1591476 • Letter: P

Question

Part A

Three equal 1.60-C point charges are placed at the corners of an equilateral triangle with sides 0.400 m long. What is the potential energy of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)

Express your answer with the appropriate units.

Also,

A particle with charge +4.20 nC is in a uniform electric field E  directed to the left. The charge is released from rest and moves to the left; after it has moved 6.00 cm, its kinetic energy is +2.20×106 J.

Part A

What is the work done by the electric force?

Express your answer with the appropriate units.

Part B

What is the potential of the starting point with respect to the end point?

Express your answer with the appropriate units.

Part C

What is the magnitude of E ?

Express your answer with the appropriate units.

Explanation / Answer

part A)

Let

Q = 1.6 micro C

d = 0.4 m

Potentail energy of charge system, U = 3*k*Q^2/d

= 3*9*10^9*(1.6*10^-6)^2/0.4

= 0.1728 J <<<<<<<------------Answer

2)

part A) Workdone by electric force = gain in kinetic energy

= 2.2*10^-6 J

B) delta_V = W/q

= 2.2*10^-6/(4.2*10^-9)

= 524 volts

C) E = delta_V/d

= 524/0.06

= 8730 N/c