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Flux and nonconducting shells. A charged particle is suspended at the center of

ID: 1591740 • Letter: F

Question

Flux and nonconducting shells. A charged particle is suspended at the center of two concentric spherical shells that are very thin and made of nonconducting material. Figure (a) shows a cross section. Figure (b) gives the net flux through a Gaussian sphere centered on the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by s = 27.0 × 105 N·m2/C. (a) What is the charge of the central particle? Give your answers in µC. What are the net charges of (b) shell A and (c) shell B?

Explanation / Answer

The region 0<r<4 inside sphere A;

Gauss says: =ds*E(,,r),

WHERE ds*E(,,r) is dot product of 2 vectors ds and E(,,r),

|ds|=r*sin*d*r*d is elementary area on a sphere with radius r

in spherical coordinate system, direction of ds being normal to the sphere,

|E(,,r)|=-q/(4*0*r^2) is strength of electric field produced by a point charge q in the center, direction of E being

normal to the sphere, 0=8.854e-12 is const,

angle is measured around z-axis as 0<=<2,

angle is measured from plane XOY as –/2<=<= /2;

(a) Since vectors ds and E(,,r) are parallel then

ds*E(,,r) = |ds|*|E(,,r)|;

= - r*sin*d*r*d * q/(4*0*r^2) =

= -q/(4*0) d sin*d = q/(4*0) d cos {=-/2 to /2} =  q/(4*0) d (1+1) {=0 to 2}

= 4*q/(4*0) = q/0 =27e5 N*m^2/C

Therefore, q = 8.854e-12*2e5 = 23.89 C

(b)   Gauss says in general: = q[k]

where, k=1 to n, n is number of charges q[k] inside of a closed surface s;

On applying,

we get q(A) = 8.854e-27*4e5 = - 7.97 C

we get q(B) = 8.854e-27*6e5 = 11.95 C