Two batteries (in series), a bulb, an uncharged capacitor, and a switch are conn
ID: 1591775 • Letter: T
Question
Two batteries (in series), a bulb, an uncharged capacitor, and a switch are connected together in a circuit with the switch open. (Note, the positive end of the battery is connected to the positive terminal of the capcitor) 1.what happens to the current in this circuit and the voltage across the bulb after the switch is closed? (Do they increase or decresae) How do your answers to question relate to the presence of the capacitor in the circuit? 2.Imagine repeating the experiment, except now with a partially-charged capacitor. How would this change your results.
Explanation / Answer
When all the components placed in series the current will remain constant throughout the circuit at any time t.
Voltage across the bulb will decreases.
As Capacitor charges its voltage increases therefore after some time when the capacitor becomes fully charged
then the voltage across the bulb will be zero or it will behave as break in circuit.
Due to partially charged capacitor the final point will achieve in less time.