Physics Electricity and Magnetism Question: A plastic rod 1.8 m long is rubbed a
ID: 1594403 • Letter: P
Question
Physics Electricity and Magnetism Question:
A plastic rod 1.8 m long is rubbed all over with wool, and acquires a charge of -6e-08 coulombs. We choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out of the page. In order to calculate the electric field at location A = < 0.7, 0, 0 > m, we divide the rod into 8 pieces, and approximate each piece as a point charge located at the center of the piece.
(a) What is the length of one of these pieces?
(b) What is the location of the center of piece number 6?
(c) How much charge is on piece number 6? (Remember that the charge is negative.)
(d) Approximating piece 6 as a point charge, what is the electric field at location A due only to piece 6?
(e) To get the net electric field at location A, we would need to calculate vector E due each of the 8 pieces, and add up these contributions. If we did that, which arrow above would best represent the direction of the net electric field at location A?
Explanation / Answer
a) 1.8/8 = 0.225m
b) (0,-3*0.225/2,0) = (0,-0.3375,0)
c) charge = Q/8 = -6e-08 /8 = -0.75*10^-8 C
d) distance = sqrt(0.3375*0.3375 + 0.7*0.7) = 0.777 m
E.F = k*q/r^2 = 9*(10^9)*0.75*(10^-8)/(0.777*0.777) = 111.80 N/c at 25.72 degree anticlockwise from -x axis
E.F = -111.80cos(25.72) i -111.80sin(25.72) j = (-100.72,-48.51) Answer
e) G (sorry about this. I forgot that rod is negatively charged)