Assign that the bulbs are identical and that each bulb is ideal.(i. e assume tha
ID: 1594942 • Letter: A
Question
Assign that the bulbs are identical and that each bulb is ideal.(i. e assume that any given bulb presents the same obstacle to the flow irrespective of the size of the flow through it) Statement 2 c refers to "other things, being equal". Two networks inside which other things are equal' are surrounded with dashed lines. This allows you to treat the network of bulbs A, C and D as a single component. In the same way, the network of bulbs B and E is also treated as a single component. This makes circuit one much simpler to think about two components in series with a battery. This is often a good way to begin thinking about a circuit if we have no information about the flow anywhere in the circuit. Of course, then you have to separately analyze the networks surrounded with dotted boxes. You'll know about the total flow from the barters front the previous step. Now you'll be m a better position to thank about haw that flow travels through each network. The network on the right is the simpler of the two. Compare the flow through B to the flow through E. Explain [1] Suppose that the flow out of the network of bulbs B and E is f. How large is the flaw through bulb B and the flow through bulb E? Explain (Give your answer in terms of f) You probably made an assumption to answer the second of these questions. You probably assumed (correctly)the sum of the flow through bulb B and the flow through bulb E was the tame as the flow into and out of theExplanation / Answer
A) Flow through B is equal to flow through E.
It is because potential difference across both are same and so is their resistance. So by Ohms law, current will also be same.
B) flow through B =f/2
flow through E =f/2
It is because flow through both bulbs are equal due to reason given in first part.