In the figure below, the mass is 4.20 kg, T = 19 N, and theta = 32 degrees. The

Question

In the figure below, the mass is 4.20 kg, T = 19 N, and theta = 32 degrees. The surface does have friction, with mu_s = 45 and mu_k = 39. If x is horizontal and y is vertical What is Tx? 16.112 N right. What is Ty? 10.068 N up. What is the Normal Force? 31.092 N up. What is the friction? 12.126 N right. What is the net force on the block in the x-direction? 3.986 N right What is the net force of the block in the y-direction? 0 N up. What is the acceleration of the block? 0.949 m/sec^2 right. What will be the position of the block after 4 seconds if it starts from a position 3 m from the left of the origin at a speed of 5 m/sec right? m right. What will be the velocity of the block at this time? m/sec right.

Explanation / Answer

here,

mass ,m = 4.2 kg

T = 19 N

theta = 32 degree

the normal reaction force , N = (m * g - T * sin(theta))

N = ( 4.2 * 9.8 - 19 * sin(32))

N = 31.1 N

d)

the static frictional force , ffs = us * N = 0.45 * 31.1 = 14 N

h)

s0 = 3 m

v0 = 5 m/s

at t = 4 s

s - s0 = v0 * t + 0.5 * a * t^2

s - 3 = 5 * 4 + 0.5 * 0.949 * 4^2

s = 30.6 m

i)

the final velocity of block , v = v0 +a * t

v = 5 + 0.949 * 4

v = 8.8 m/s

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