In the figure, block 1 has mass m_1 = 487 g, block 2 has mass m_2 = 500 g, and t

Question

In the figure, block 1 has mass m_1 = 487 g, block 2 has mass m_2 = 500 g, and the pulley is on a frictionless horizontal axle and has radius R = 4.79 cm. When released from rest, block 2 falls 70.4 cm in 5.38 s without the cord slipping on the pulley. What is the magnitude of the acceleration of the blocks? What are tension T_2 (the tension force on the block 2) and tension T_1 (the tension force on the block 1)? What is the magnitude of the pulley's angular acceleration? What is its rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s^2 Number ___________ Units _____________ Number ___________ Units _____________ Number ___________ Units _____________ Number ___________ Units _____________

Explanation / Answer

A) s = ut + 0.5*at^2

So, 0.704 = 0 + 0.5*a*5.38^2

So, a = 0.049 m/s2

B)

For mass 2:

m2*g - T2 = m2*a

So, T2 = m2*(g - a) = 0.5*(9.8-0.049) = 4.88 N

C)

For mass m1:

T1 - m1*g = m1*a

So, T1 = M1*(g+a) = 0.487*(9.8+0.049) = 4.8 N

D)

Angular acceleration , A = a/R

= 0.049/0.0479

= 1.02 rad/s2

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