Playing in the street, a child accidentally tosses a ball (mass m) with a speed
ID: 1600216 • Letter: P
Question
Playing in the street, a child accidentally tosses a ball (mass m) with a speed of v=25 m/s toward the front of a car (mass M) that is moving directly toward him with a speed of V=21 m/s . Treat this collision as a 1-dimensional elastic collision. After the collision, the ball is moving with speed v back toward the child and the car is moving with speed V in its original direction.
When we combine the equation from Part A with the conservation of momentum equation, we can solve for both final speeds. This relationship will involve the masses of the ball and the car, but we can apply a simplifying assumption: the car is so massive compared with the ball that its speed will not change at all as a result of this collision. Translate this sentence into an equation, what is V equal to? Now, having made this assumption, it becomes possible to solve the equation from Part A for the final speed of the ball, what is it?
Explanation / Answer
The force between the two items for a given measure of time. Now and again, the time is long; in different cases the time is short. Notwithstanding to what extent the time is, one might say that the time that the drive follows up on protest 1 is equivalent to the time that the compel follows up . As a condition, this can be expressed as
F1=-F2
Since the powers between the two items are equivalent in greatness and inverse in heading, and since the circumstances for which these strengths demonstration are equivalent in extent, it takes after that the driving forces experienced by the two articles are additionally equivalent in size and inverse in course. As a condition, this can be expressed as
T1=-T2
In any case, the motivation experienced by a protest is equivalent to the adjustment in energy of that question (the drive force change hypothesis). In this way, since each question encounters equivalent and inverse motivations, it takes after consistently that they should likewise encounter equivalent and inverse energy changes. As a condition, this can be expressed as
mxdelta V1=Mxdelta v2
mx25=Mx21