Consider a singly charged potasium ion (K+) sent into a uniform electric field w
ID: 1600718 • Letter: C
Question
Consider a singly charged potasium ion (K+) sent into a uniform electric field with a velocity v(K+) as shown in the diagram below. The trajectory of the cation is such that it starts at the bottom and just clears the upper edge as it leaves the field as indicated by the dashed line. If a calcium ion (Ca2+) is injected into the field, what must its velocity be (relative to that of the singly charged K+) such that it follows the same trajectory (ignore the small difference in the masses)?
a. v(Ca2+) = 4 v(K+)
b. v(Ca2+) = 2 v(K +)
c. v(Ca2+) = 2 v(K +)
d. v(Ca2+) = (1/2 ) v(K +)
e. v(Ca2+) = (1/2) v(K +)
y(K)Explanation / Answer
If we consider there is small mass difference, so we can not consider it.
Because of Ca is 2+ ions so its speed will be double than K+ ion
So, option e is correct
e. v(Ca2+) = (1/2) v(K +)