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Question
IAS 2003-003 x Maormillan Launchpad: Login x G sign in to your accourt The Expert TAI Human-like G x C Search Textbook Solutions x Class Management I Help Homework 7 Begin Date: 3/12/2017 7:00:00 AM Due Date: 3/27/2017 11:59:00 PM End Date: 3/27/2017 11:59.00 PM (8%) Problem 12: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (eft lens) and 40.5 cm (right lens) are separated by a distance 25 cm. Otheexpertta.com 13% Part (a) If an object is placed a distance do fi to the left of the first lens (the left lens), will the resulting image from the first lens be real or virtual, and inverted or upright? s 0.39 cm tall, what is the magnification of the cm tall object is placed as indicated in part (a), and the image formed first lens? 13% Part (e) Using the information from part (b), calculate the image distance, in centimeters, from the first lens. 13% Part d) Does the image formed by the first lens serve as a real or a virtual objectfor the second lens? 13% Part (e) What is the image distance. in centimeters, for the second lens? Grade Summary dia 162 100% 7 8 9 HoME sin00 Attempts remaining: 14 cotano asino acos0 (09 per attempt) detailed atano acotano Lsinho tanho cotan ODegrees Radians deduction per feedback Hints: deduction per hint. Hints remaining: 2 Feedback A 13% Part (n What is the magnification of the second lens? 13% Part What is the total magnification of this compound optical system?Explanation / Answer
(A) 1/f = 1/di + 1/do
di = (d0)(f) / (do - f)
d0 > f So di will be positive.
hence image will be real.
(B) m = - 0.39 / 2.5 = - 0.156
(C) m = - di / do
do = - di / (-0.156) = 6.41di
1/7.5 = 1/di + 1/6.41di
di = 8.67 cm
(D) imaage formes by first lens is to the left from 2nd lens.
hence it will be a real object.
(E) do2 = 25 - 8.67 = 16.33 cm
1/40.5 = 1/16.33 + 1/di2
di2 = -27.4 cm
27.4 cm from 2nd lens to the left of second lens.
(F) m = - (-27.4) / 16.33 = 1.68
(g) m = -0.156 x 1.68 = - 0.26
(h) Virtual. inverted