Part e f g Class Management I Help (20%) Problem 5: Using special techniques cal
ID: 1605069 • Letter: P
Question
Part e f g Class Management I Help (20%) Problem 5: Using special techniques called string harmonics (or flageolet tones"),stringed instruments can produce the first few overtones of the harmonic series. While a violinist is playing some of these harmonics for us, we take a picture of the vibrating string (see figures. Using an osciliscope we find the violinist plays a note with frequency 830 Hz in figure (a). otheexpertta-coni 14% Part (a) How many nodes does the standing wave in figure (a) have? 14% Part (b) How many antinodes does the standing wave in figure (a) have? wave in figure (a) in meters? 14% Part (e) The length of a violin is about L-33 cm. What is the wavelength of the standing fundamental 14% Part (d) The fundamental frequency is the lowest frequency that a string can vibrate at (see figure (b). What is the leted pleted. frequency for our violin in Hz? the note the violinist is playing in figure (c)? 4 14% Part (e) In terms of the fundamental frequency fr what is the frequency of pleted Deduction" 100s 7 8 9Explanation / Answer
e) In fig C) ,the string was vibrating with two loops,hence it's frequency is f2 = 2*f1 where f1 is the fundamental frequency
f) if the string is vibrating with n loops or segments,then it's frequency is fn = n*f1
no.of antinodes is 2n antinodes in case of a standing wave
g) fundamental frequency is f1 = 830/4 = 207.5 Hz
in fig d)
the string is vibrating with 8 loops
then f8 = 8*207.5 = 1660 Hz