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In the figure, a string, tied to a sinusoidal oscillator at P and running over a

ID: 1606451 • Letter: I

Question

In the figure, a string, tied to a sinusoidal oscillator at P and running over a support at Q, is stretched by a block of mass m. Separation L = 1.4 m, near density mu = 0.8 g/m, and the oscillator frequency f = 140 Hz. The amplitude of the motion at P is small enough for that point to be considered a node. A node also exists at Q. (a) What mass m allows the oscillator to set up the fourth harmonic on the string? (b) What standing wave mode, if any, can be set up if m = 3 kg (Give 0 if the mass cannot set up a standing wave)?

Explanation / Answer

Given that L=1.4m

=0.8g/m=0.0008kg/m

f=140HZ

a)

f=(nv/2)/L

where V=sqrt(mg/)

given n=4 (fourth harmonic)

f=[((nxsqrt(mg/))/2]/L

2fL/n=sqrt(mg/)

m=((2fL/n)2 x)/g

=(((2x140x1.4)/4)2 x0.0008)/9.8

m=0.784 kg

b)

here given m=3kg

string tension T=mg

T=3x9.8=29.4 N

V=sqrt(mg/)

=(29.4/0.0008)

V=191.7m/s

=v/f

=191.7/140

=1.37m