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Please help me out. I am very confused so please also explain what youre doing.

ID: 1610479 • Letter: P

Question

Please help me out. I am very confused so please also explain what youre doing.

An E guitar string of length 70 cm is fixed at both ends. Its fundamental frequency (frequency of the fundamental harmonic) is f = 330 Hz.

1) What is the wavelength of the fundamental oscillation of this string?

a. = 175 cm

b. = 35 cm

c. = 70 cm

d. = 105 cm

e. = 140 cm

2) What is the velocity of a wave travelling in the string?

a. v = 684 m/s

b. v = 462 m/s

c. v = 200 m/s

3) The string is retuned. The new tension is T' = 4T. What is the new fundamental frequency of the string, f'?

a. f' = 2f

b. f' = f/4

c. f' = 4f

d. f' = f e. f' = f/2

4) The string is replaced with a new string. The new string has the same length (70 cm) and tension T. It has four times the mass, M'' = 4M. What is the new fundamental frequency of the string, f''?

a. f'' = f/2

b. f'' = 2f

c. f'' = f

d. f'' = 4f

e. f'' = f/4

Explanation / Answer

1) fundamental frequency is f = v/2L ------------ (1)

where v is the speed of the wave, We know that

f = v (for a wave, frequencyXwavelength = speed of wave)

So, = v/f

So from equation (1) we have v/f = 2L = 2(70cm) = 140cm

So   = v/f = 140cm

So option e) is correct.

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2) from equation (1) above we have, v = 2Lf = 2(70cm)(330Hz) =2(0.7m)(330Hz) = 462m/s

So, option b) is correct.

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3) For a wave speed of wave v = [T/µ], where T is the tension, µ is mass per unit length of string.

New tension is T' = 4T, putting this value of tension in above formula we get new speed of the wave v',

whre v' = [4T/µ] = 2[T/µ] = 2v, so the speed is doubled, if tension is quadrupled.

Now we know that, fundamental frequency is f = v/2L

So new fundamental frequency is f' = v'/2L = 2v/2L = v/L, thus the fundamnetal frequency is doubled.

So, option a) is correct.

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4)  initially, mass per unit length of string µ = M/L

New mass per unit length of string is µ' = 4M/L = 4µ (length is same for both strings)

So the new speed v' = [T/4µ] = (1/2)[T/µ] = v/2

So the new fundamental frequency is f' = v'/2L = (v/2)/2L = f/2

So, option a) is correct.

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This concludes the answers. Check the answer and let me know if it's correct. If you need anymore clarification or correction I will be happy to oblige....