Please I want someone to answer it clearly and step by step A 20-kg block slides

Question

Please I want someone to answer it clearly and step by step

A 20-kg block slides 12 m along a frictionless ramp inclined at 30 degree to the horizontal. At the bottom, after reaching a horizontal surface, the block makes a perfectly inelastic collision with a 30-kg block attached to a spring. The horizontal surface is also frictionless, and the spring constant is 5000 N/m. (a) What is the speed of the 20-kg block when it reaches the bottom of the ramp? (b) What is the speed of the pair of blocks just after they collide? (c) How much is the spring compressed?

Explanation / Answer

a)VELOCITY OF 20 KG BLOCK WHEN IT REACHES BOTTOM IS

V=SQRT(20X9.8SIN30X12)=9.9M/S

the 20kg block collide inelastically with 30 kg block which is attached to spring

b)coommon velocity of blocks just after collisin is

v=(20x9.9)/(20+30)=1.58m/s

c)x=compression in the spring=(50x1.582)/5000=0.025088m=2.5cm

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