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Pipe (Dynamic Fluids) A pipe with a diameter of D1 = 10 cm rises vertically a he

ID: 1612235 • Letter: P

Question

Pipe (Dynamic Fluids) A pipe with a diameter of D1 = 10 cm rises vertically a height H = 4.8 m and expands to a pipe of D2 = 28 cm in diameter. The flow rate of the fluid through the pipe is 8×102 cubic meters per second. The pressure in the lower end of the pipe is 1.2×105 Pascals. The fluid has a density of 1200 kg/m3 ..

1. Find the velocity of the fluid in the lower section of the pipe.


v1=__ m^s

2. Find the difference in hydrostatic pressure from the high section to the low section.

p_H=__ Pascals

3. Find the pressure in the upper section of the pipe.

What is the weight of the fluid that passes through the pipe in 15 minutes ?

P2 = __ Pascals D H D1 2

Explanation / Answer

1) flow rate =Area*Velocity

8*10^-2 =pi*0.1*0.1*v

v2=2.55 m/s

v1=(8/pi)*(1/2.82)=0.325

2)P1 + 0.5pv12+pgH=P2 + 0.5pv22 + pg(0)

P1-P2=0.5*1200*(2.552-0.3252)-1200*9.8*4.8= -52609.875 Pa

3)P1=67390.125 Pa pressure in upper section

weight of fluid passing in15 minutes=p*Q*t=1200*8*10^-2 *15*60=86400 N