In a Young\'s double-slit experiment, two parallel slits with a slit separation
ID: 1615086 • Letter: I
Question
In a Young's double-slit experiment, two parallel slits with a slit separation of 0.145 mm are illuminated by light of wavelength 599 nm, and the interference pattern is observed on a screen located 3.70 m from the slits. (a) What is the difference in path lengths from each of the slits to the location of the center of a third-order bright fringe on the screen? mu m (b) What is the difference in path lengths from the two slits to the location of the center of the third dark fringe away from the center of the pattern? mu mExplanation / Answer
d = 0.145 mm ; lambda = 599 nm ; D = 3.7 m
a)m = 3
Path diff would be simply
delta = m lambda
delta = 3 x 599 = 1797 nm = 1.797 um
Hence, delta = 1.797 nm
b)In this case, m = 2.5
delta = m lambda
delta = 2.5 x 599 = 1497.5 nm = 1.498 um
Hence, delta = 1497.5 nm = 1.498 um