Please explain how to do this. When released from rest at point A, a proton flie
ID: 1616958 • Letter: P
Question
Please explain how to do this. When released from rest at point A, a proton flies to point B. The potential at point A is 60 V. The potential difference between points A and B is 20 V (plus or minus). What is the potential at point B? Explain. What is the change in potential energy in Joules as the proton in goes from A to B? Is this an increase or decrease in potential energy? What is the change in potential energy in eV? What is the external work done as the proton goes from A to B? What is the change in the proton's kinetic energy in eV in going from A to B?Explanation / Answer
Given that
potential at point Va=60 v
potential at point Vab=20 v
basing on the concept of electric potential
now we find the potential at point B
potential at point B=>Vb=Vab+Va=20+60=80 v
the proton goes from A to B is decreases
=>the change in potential energy =the external work done=q[Vb-va]=1.6*10^-19*20=32*10^-19 J
=>the change in kinetic energy=32*10^-19/1.6*10^-19=20eV