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I need someone to show me the process of solving problems like this. I don\'t re

ID: 1619112 • Letter: I

Question

I need someone to show me the process of solving problems like this. I don't really care for the answer. The answer is already on the question.

2. One and one-half moles of an ideal gas undergo the cyclic process shown below. The initial pressure and volume of the gas are 5.00x105 N/m2 and 0.01m3, respectively. 5.00x10 I------ 1.00x10 0.01 0.05 V(ms) a. Calculate the initial temperature of the ideal gas. Note:R-8.314 J/k-moE0.0821L-atm/mol- K. At what point in the cycle is the temperature of the gas a minimum? (5 points) 401K b. Calculate the WAB, WBc, WCA, WcycLE, and QCYCLE (15 points) 12,000J -4000 8000 8000 J

Explanation / Answer

okay , for the first part a) use the ideal gas law to find the value of temperature T for points A , B and C ,

PV= nRT we have known values of P (pressure) N/m2 , V (volume) in m3 , n (number of moles) = 1.5 , use R =8.314 J/k.mol ( Since all the quantities are given in SI units.)

For work done ,

First calculate the area enclosed by the P-V curve , that is , the area of the triangle , this will give the value of net work done (put positive sign if the process is clockwise and negative sign if the process is counter-clockwise) , in this case the process is clockwise so put sign of net work done must be positive. Wnet = area enclosed by the P-V curve.

Now , calculate work done for C>>>A process , which will be zero WCA =0 , since no volume change is occurring, then calculate work done for B>>>C process WBC = P(Vc - VB) Joules

So , by now you have work done for whole process , and for C>>>A and B>>>C , so For A>>>B process use

Wnet = WAB + WBC +WCA  

After calculating all the work done your problem is all solved .

For internal energy calculation, KNOW THAT change in internal energy U for a whole cycle is zero , since internal energy is a state function and for a cycle initial and final state are same

Finally for heat , APPLY FIRST LAW OF THERMODYNAMICS,  U=Q - W = 0

SO , Qcycle = Wcycle

Hope this is what you asked for . please provide feedback . comment if something is not clear .