In the figure below, a metal conducting rod connects two conductors held at a po

Question

In the figure below, a metal conducting rod connects two conductors held at a potential difference of 1.2 V. There is also a uniform magnetic field directed into the page with magnitude 0.80 T. When you place the rod as shown in the diagram, current begins running through it. You happen to know that the resistance of the rod is 2.4 Ohm, its mass is 50 g, and its length is 15 cm. a) Calculate the current running through the conducting rod. b) Calculate the magnetic force acting on the road. c) Calculate the speed that the rod would be shot out at if we turn the magnetic field off after 2.0 seconds.

Explanation / Answer

Here ,

V = 1.2 V

B = 0.80 T

R = 2.4 Ohm

m = 0.050 Ohm

L = 0.15 m

a) current running = V/R

current running = 1.2/2.4

current running = 0.50 A

b)

magnetic force acting on the rod = BI*L

magnetic force acting on the rod = 0.80 * 0.50 * 0.15

magnetic force acting on the rod = 0.06 N

c)

speed of the rod = acceleration * time

speed of the rod = 0.06/(0.050) * 2

speed of the rod = 2.4 m/s

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---